In the figure, the tension in the horizontal cord is $30\,N$. Find the weight of the body $B$.

$A$ mass of $10 \, kg$ is suspended vertically by a rope of length $5 \, m$ from the roof. $A$ force of $30 \, N$ is applied at the middle point of the rope in the horizontal direction. The angle made by the upper half of the rope with the vertical is $\theta = \tan^{-1}(x \times 10^{-1})$. The value of $x$ is ................
(Given $g = 10 \, m/s^2$)

The following forces start acting on a particle at rest at the origin of the coordinate system simultaneously: ${\vec F_1} = -4\hat i - 5\hat j + 5\hat k$,${\vec F_2} = 5\hat i + 8\hat j + 6\hat k$,${\vec F_3} = -3\hat i + 4\hat j - 7\hat k$,and ${\vec F_4} = 2\hat i - 3\hat j - 2\hat k$. The particle will move:

As shown in the figure,the two sides of a step ladder $BA$ and $CA$ are $1.6 \; m$ long and hinged at $A$. $A$ rope $DE$ of length $0.5 \; m$ is tied halfway up. $A$ weight of $40 \; kg$ is suspended from a point $F$,$1.2 \; m$ from $B$ along the ladder $BA$. Assuming the floor to be frictionless and neglecting the weight of the ladder,find the tension in the rope and the forces exerted by the floor on the ladder. (Take $g = 9.8 \; m/s^2$)

$A$ body is in equilibrium under the action of three coplanar forces $P, Q$ and $R$ as shown in the figure. Select the correct statement.

$A$ book of mass $5 \,kg$ is placed on a table and it is pressed by $10 \,N$ force. Then,the normal force exerted by the table on the book is ......... $N$.